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Problem 2: What does that tell you about the possibility that just two sexes are important, with B dominant over b?

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Problem 3: Now suppose you do a third breeding experiment in which you start with S1, S2 and S5 having the value B whereas S3 and S4 have the value b, then all 1,000 children in the next generation have the b phenotype. This is different! In the following generation, 26% have the B phenotype and 74% have the b phenotype. Crossing the B phenotype children gives more than 15% that have the b phenotype – symmetric to the other case. Can you make a good hypothesis about which parents determine the trait value and what the rule is for which trait will show up?

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1 Comments

1. 1. ZenaV 04:03 PM 12/10/08

   Hmm....sounds like a formula that would breed mental illness....actually it sound polygamous...

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